Broadcom Hiring Freshers, Jobs in Bangalore

Location : Bangalore
 

Role : Intern

Qualification : BE / B.tech / ME / M.tech 

Skills :

• Must be from 2013 / 2014 Batch Only
• Must have good programming skills in c and Scripting language
• Understanding of ARM architecture and linux desired
• Must have good communication skills.
• Must be a team player

CTC : As per company norms

Last Date : ASAP

To Apply : Click Here

Sumudra technologies Hiring Freshers as SEO Executive

Location : Hyderabad

Role : SEO Executive

Qualification : Any Graduate

Skills : 

1. Position for sEO and internet marketing , outstanding ability to think creatively and identify and resolve problems
2. On Page and off page SEO work , directory submission ,. classified posting , Article , Blog Submission
3. If you are looking to grow with a product company and have excellent background in SEO. we need you

CTC : As per industry

Walk-in Date : 18-April-2014

Walk-in Time : 9 am onwards

Contact person : Mr. Sudheer

Contact Details : 040-40214449

*Call Mr Sudheer and ask for venue details *

Digiapt Off Campus for freshers for the post of Associate solution developer

Location : Bangalore

Role : Associate Solution Developer

Qualification : BE / B.tech 

Skills :

1. Good Communication skills.
2. Strong problem solving skills.
3. Good understanding of data structures and algorithm.
4. Excellent coding skills.
5. Excellent code comprehension skills.
6. Must be a quick learner.
7. Self motivated with desire to excel.
8. Willingness to receive feedback.
9. Must be a team player.
10. Must communicate with team members effectively.

Last Date :  ASAP

CTC : Best in industry

About DigiApt :

DigiApt is a software services company , primarily focused on building innovative software products by applying best in class technologies, processes, and people.

Our strength lies in applying open source technologies with agile development process.

To Apply Click Here

C program to find sum of odd numbers and even numbers from 1 to N

/* Write a C program to find the sum of odd numbers and even numbers from 1 to N */


#include
#include

void main ()
{
                 int i, N, oddsum=0, evensum=0;
                clrscr();
                           printf("enter the value for N \n");
                           scanf("%d", &N);

for (i=0;i<=N;i++)
               { 
                          if(i % 2 == 0)
                          evensum = evensum +1; 
                          else
                          oddsum = oddsum+1;
                 }

printf("Sum of all odd numbers is = "%d\n ", oddsum);

printf("sum of all even numbers is = "%d\n", evensum);

}


/* sample output */


enter the value of N
10
sum of all odd numbers in = 25
sum of all even numbers is = 30